Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises: 72

Answer

$(2x^{2}y)^{\frac{1}{3}}=2^{\frac{1}{3}}x^{\frac{2}{3}}y^{\frac{1}{3}}$

Work Step by Step

Step 1: The index of the radical is 3, so the denominator of the fractional exponent is 3. Step 2: Therefore, the expression is written as $(2x^{2}y)^{\frac{1}{3}}$. Step 3: $(2x^{2}y)^{\frac{1}{3}}=2^{\frac{1}{3}}x^{\frac{2}{3}}y^{\frac{1}{3}}$
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