Answer
See graph
Work Step by Step
Given \begin{equation}
y=2 x^2-4 x-18.
\end{equation} This is an equation of a parabola in standard form. Let's determine the vertex so that we can mark it on the graph. The $x$ and $y$ of the vertex are found from \begin{equation}
\begin{aligned}
x&=\frac{-b}{2a}\\
&= -\frac{(-4)}{2(2)} \\
& =1\\
y&=2\cdot 1^2-4\cdot 1-18\\
y &= -20.
\end{aligned}
\end{equation} The vertex is $(1,-20)$.
The graph of the function is shown in the figure below with the horizontal and vertical intercepts labelled. The vertex is also labelled.
