Answer
$ \begin{bmatrix}
1&-3 &-5 \\
0 & -1 & 31 \\
\end{bmatrix}$
Work Step by Step
The augmented matrix is
$\begin{bmatrix}
1&-3 &-5 \\
3 & -10 & 16 \\
\end{bmatrix}$
Perform the given operations.
$R_2\rightarrow R_2-3R_1$
$\Rightarrow \begin{bmatrix}
1&-3 &-5 \\
3-3(1) & -10-3(-3) & 16-3(-5) \\
\end{bmatrix}$
Simplify.
$\Rightarrow \begin{bmatrix}
1&-3 &-5 \\
0 & -10+9 & 16+15 \\
\end{bmatrix}$
$\Rightarrow \begin{bmatrix}
1&-3 &-5 \\
0 & -1 & 31 \\
\end{bmatrix}$
The above matrix is the upper triangular form.
