Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix B - Matrices - B Exercises - Page B-15: 31

Answer

$(x,y)=(-2,-5)$.

Work Step by Step

The augmented matrix is $\begin{bmatrix} 4&-3 &7 \\ 0 & -1 & 5 \end{bmatrix}$. For the linear equation. First column $=$ coefficients of $x$. Second column $=$ coefficients of $y$ and third column $=$ the right-hand side. The given matrix is a upper triangular form. Rewrite the second row as a linear equation. $\Rightarrow 0x-1y=5$ $\Rightarrow -y=5$ Multiply the equation by $-1$. $\Rightarrow -1(-y)=-1(5)$ Simplify. $\Rightarrow y=-5$ Rewrite the first row as a linear equation. $\Rightarrow 4x-3y=7$ Substitute $y=-5$. $\Rightarrow 4x-3(-5)=7$ Clear the parentheses. $\Rightarrow 4x+15=7$ Subtract $15$ from both sides. $\Rightarrow 4x+15-15=7-15$ Simplify. $\Rightarrow 4x=-8$ Divide both sides by $4$. $\Rightarrow \frac{4x}{4}=\frac{-8}{4}$ Simplify. $\Rightarrow x=-2$ The solution set is $(x,y)=(-2,-5)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.