Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix B - Matrices - B Exercises - Page B-15: 32

Answer

$(x,y)=(0,0)$.

Work Step by Step

The augmented matrix is $\begin{bmatrix} 5&-1 &0 \\ 0 & 2 & 0 \end{bmatrix}$. For the linear equation. First column $=$ coefficients of $x$. Second column $=$ coefficients of $y$ and third column $=$ the right-hand side. The given matrix is a upper triangular form. Rewrite the second row as a linear equation. $\Rightarrow 0x+2y=0$ $\Rightarrow 2y=0$ Divide the equation by $2$. $\Rightarrow \frac{2y}{2}=\frac{0}{2}$ Simplify. $\Rightarrow y=0$ Rewrite the first row as a linear equation. $\Rightarrow 5x-1y=0$ $\Rightarrow 5x-y=0$ Substitute $y=0$. $\Rightarrow 5x-(0)=0$ Clear the parentheses. $\Rightarrow 5x=0$ Divide both sides by $5$. $\Rightarrow \frac{5x}{5}=\frac{0}{5}$ Simplify. $\Rightarrow x=0$ The solution set is $(x,y)=(0,0)$.
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