Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 706: 67

Answer

$$-\frac{1}{5},\frac{1}{6},-\frac{1}{7},\frac{1}{8},-\frac{1}{9}$$

Work Step by Step

We plug in the different values of n to find the first 5 terms: $$ a_1=\frac{(-1)^1}{1+4} = -\frac{1}{5} \\ a_2=\frac{(-1)^2}{2+4} = \frac{1}{6} \\ a_3=\frac{(-1)^3}{3+4} = -\frac{1}{7} \\ a_4=\frac{(-1)^4}{4+4} = \frac{1}{8} \\ a_5=\frac{(-1)^5}{5+4} = -\frac{1}{9} $$
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