Answer
$(g\circ h)(x)=x^2-6x-2$
Work Step by Step
With $g(x)=x-7$ and $h(x)=x^2-6x+5$, then
\begin{array}{l}\require{cancel}
(g\circ h)(x)=g(h(x))
\\\\
(g\circ h)(x)=g(x^2-6x+5)
\\\\
(g\circ h)(x)=(x^2-6x+5)-7
\\\\
(g\circ h)(x)=x^2-6x-2
.\end{array}
