Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 706: 48

Answer

5 gallons of 10% and 15 gallons of 20% are needed.

Work Step by Step

$17.5\%$ is 3/4 of the way between 20 percent and 10 percent. Thus, of the 20 gallons, 3/4 must be the 20 percent solution. Thus: $$ Amount \ of \ 20\%: \\ = (20 \ gallons)(.75) \\ = 15\ gallons $$ So: $$ Amount \ of \ 10\%: \\ = (20 \ gallons)(.25) \\ = 5\ gallons $$
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