Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 706: 44

Answer

$x=5$

Work Step by Step

Let the unknown number be $x$. One more than the number= $x+1$. Twice the reciprocal of the number= $2(\frac{1}{x})=\frac{2}{x}$. The product of one more than a number and twice the reciprocal of the number is $\frac{12}{5}$ means: $(x+1)\times\frac{2}{x}=\frac{12}{5}$ Solving this equation: Step 1: $\frac{2(x+1)}{x}=\frac{12}{5}$ Step 2: $\frac{2x+2}{x}=\frac{12}{5}$ Step 3: $5(2x+2)=12x$ Step 4: $10x+10=12x$ Step 5: $12x-10x=10$ Step 6: $2x=10$ Step 7: $x=5$
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