Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 706: 47b

Answer

$$t=5.12 \ seconds$$

Work Step by Step

The stone hits the water at the time where the height is 0 and $t>0$. Thus, we find: $$ 0=-16t^2+ 32t + 256 $$ Applying the quadratic formula: $$ t_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ t_{1,\:2}=\frac{-32\pm \sqrt{32^2-4(-16)256}}{2(-16)} \\ t=1\pm \sqrt{17} $$ Since $t$ must be positive: $$ t=1+\sqrt{17} \\ t=5.12 \ seconds$$
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