Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 706: 47a

Answer

The maximum height is 272 feet.

Work Step by Step

We know the location of the vertex is $-\frac{b}{2a}$. Thus: $$ t_{critical}=-\frac{32}{(-16)(1)}\\ t_{critical}=1\ s$$ The maximum occurs at 1 second. Thus, we plug 1 second into the original function: $$ s(1) = (-16)(1^2) + 32(1) + 256 \\ = 272\ ft$$
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