Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 706: 70

Answer

10

Work Step by Step

Solving using the sum rule, we find: $$ \sum _{i=1}^4i(i-2) \\ =\sum _{i=1}^4i^2-2i \\ =\sum _{i=1}^4i^2-\sum _{i=1}^42i \\ =30-20 \\ =10$$
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