Answer
4.4 and 1.6
Work Step by Step
We are given:
$$y=3x^2-18x+56$$
Where x is the day and y is the temperature. We want to find when the temperature was 35, so:
$$0=3x^2-18x+21$$
We use the quadratic formula
$$x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
Where b is the coefficient of the term with a variable raised to the first power, a is the coefficient of the squared term, and c is the coefficient of the term without a variable in front of it.
This helps us arrive at the answer of:
4.4 and 1.6
