Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.2 - Solving Quadratic Equations by the Quadratic Formula - Exercise Set - Page 494: 68

Answer

$y=23$

Work Step by Step

Using the properties of equality, the given equation, $ \sqrt{y+2}+7=12 ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt{y+2}=12-7 \\\\ \sqrt{y+2}=5 .\end{array} Squaring both sides of the equation above results to \begin{array}{l}\require{cancel} \left( \sqrt{y+2} \right)^2=(5)^2 \\\\ y+2=25 \\\\ y=25-2 \\\\ y=23 .\end{array} Upon checking, $ y=23 $ satisfies the original equation.
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