Intermediate Algebra (6th Edition)

The given set of values is an incorrect substitution for $a, b,$ and $c$ in the standard form $ax^2+bx+c=0$ because $b=1$, not $-1$.
RECALL: The standard form of a quadratic equation is $ax^2+bx+c=0$ Write the given quadratic in equation in standard form to obtain: $x^2+5=-x \\x^2+5+x=-x+x \\x^2+5+x=0 \\x^2+x+5=0$ The quadratic equation above has: $a=1, b=1, c=5$ Thus, the given set of values is an incorrect substitution for $a, b,$ and $c$ in the standard form $ax^2+bx+c=0$.