Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.2 - Solving Quadratic Equations by the Quadratic Formula - Exercise Set: 76b

Answer

The given set of values is an incorrect substitution for $a, b, $ and $c$ in the standard form $ax^2+bx+c=0$ because $b=1$, not $-1$.

Work Step by Step

RECALL: The standard form of a quadratic equation is $ax^2+bx+c=0$ Write the given quadratic in equation in standard form to obtain: $x^2+5=-x \\x^2+5+x=-x+x \\x^2+5+x=0 \\x^2+x+5=0$ The quadratic equation above has: $a=1, b=1, c=5$ Thus, the given set of values is an incorrect substitution for $a, b, $ and $c$ in the standard form $ax^2+bx+c=0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.