#### Answer

The given set of values is an incorrect substitution for $a, b, $ and $c$ in the standard form $ax^2+bx+c=0$ because $b=1$, not $-1$.

#### Work Step by Step

RECALL:
The standard form of a quadratic equation is $ax^2+bx+c=0$
Write the given quadratic in equation in standard form to obtain:
$x^2+5=-x
\\x^2+5+x=-x+x
\\x^2+5+x=0
\\x^2+x+5=0$
The quadratic equation above has:
$a=1, b=1, c=5$
Thus, the given set of values is an incorrect substitution for $a, b, $ and $c$ in the standard form $ax^2+bx+c=0$.