Answer
The given set of values is an incorrect substitution for $a, b, $ and $c$ in the standard form $ax^2+bx+c=0$ because $a=1$, not $0$.
Work Step by Step
RECALL:
The standard form of a quadratic equation is $ax^2+bx+c=0$
Write the given quadratic in equation in standard form to obtain:
$x^2=-10
\\x^2+10=-10+10
\\x^2+10=0$
The quadratic equation above has:
$a=1, b=0, c=10$
Thus, the given set of values is an incorrect substitution for $a, b, $ and $c$ in the standard form $ax^2+bx+c=0$.
