Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.2 - Solving Quadratic Equations by the Quadratic Formula - Exercise Set - Page 494: 80

Answer

x=.9, -1.4

Work Step by Step

We are asked to substitute a, b, and c into the quadratic formula: $$x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$ Where b is the coefficient of the term with a variable raised to the first power, a is the coefficient of the squared term, and c is the coefficient of the term without a variable in front of it. $$x= \frac{-1.8 \pm \sqrt{1.8^2-4(3.6)(-4.3)}}{2(3.6)}$$ Simplifying gives: x=.9, -1.4
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