Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 97



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{7x^{-1}y}{14(x^5y^2)^{-2}} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{7x^{-1}y}{14(x^{5(-2)}y^{2(-2)})} \\\\= \dfrac{7x^{-1}y}{14x^{-10}y^{-4}} \\\\= \dfrac{7x^{-1-(-10)}y^{1-(-4)}}{2} \\\\= \dfrac{7x^{-1+10}y^{1+4}}{2} \\\\= \dfrac{7x^{9}y^{5}}{2} .\end{array}
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