Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 106


Choice C

Work Step by Step

Using the properties of radicals, the expression, $ \sqrt[]{8} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[]{4\cdot2} \\\\= \sqrt[]{(2)^2\cdot2} \\\\= 2\sqrt[]{2} .\end{array} Since this is not a whole number, then $\text{ Choice C .}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.