## Intermediate Algebra (6th Edition)

Using the properties of radicals, the expression, $\sqrt[]{8} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[]{4\cdot2} \\\\= \sqrt[]{(2)^2\cdot2} \\\\= 2\sqrt[]{2} .\end{array} Since this is not a whole number, then $\text{ Choice C .}$