Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 104

Answer

Choice C

Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt[3]{27} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{(3)^3} \\\\= 3 .\end{array} Hence, $\text{ Choice C .}$
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