## Intermediate Algebra (6th Edition)

Approximately $2,374$ m/s.
Given formula: $v=\sqrt\frac{2Gm}{r}$, where $m$ is the mass of the planet, $r$ is its radius, and $G$ is the universal gravitational constant, which has a value of $G = 6.67 \times 10^{-11}$m$^{3}/$kg$\times$s$^{2}$. Substitute the values from the question into the formula. $v=\sqrt\frac{2(6.67\times10^{-11})(7.35\times10^{22})}{1.74\times10^{6}}$ $v\approx2,374$ The escape velocity is approximately $2,374$ m/s.