Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 109

Answer

Choice B

Work Step by Step

The given expression, $ \sqrt[]{30} ,$ is closest to $5$ since $5^2=25.$ The given expression, $ \sqrt[]{10} ,$ is closest to $3$ since $3^2=9.$ The given expression, $ \sqrt[]{90} ,$ is closest to $10$ since $10^2=100.$ Hence, the perimeter of the given triangle, $ \sqrt{30}+\sqrt{10}+\sqrt{90} ,$ is closest to \begin{array}{l}\require{cancel} 5+3+10 \\\\= 18 .\end{array} Hence, $\text{ Choice B .}$
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