Answer
Approximately $11,181$ m/s.
Work Step by Step
Given formula: $v=\sqrt\frac{2Gm}{r}$, where $m$ is the mass of the planet, $r$ is its radius, and $G$ is the universal gravitational constant, which has a value of $G = 6.67 \times 10^{-11}$m$^{3}/$kg$\times$s$^{2}$.
Substitute the values from the question into the formula.
$v=\sqrt\frac{2(6.67\times10^{-11})(5.97\times10^{24})}{6.37\times10^{6}}$
$v=11,181$
The escape velocity is approximately $11,181$ m/s.
