Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 418: 110

Answer

Choice C

Work Step by Step

The given expression, $ \sqrt[]{8} ,$ is closest to $3$ since $3^2=9.$ The given expression, $ \sqrt[]{20} ,$ is closest to $4$ since $4^2=16.$ Hence, the length of the bent wire, $ \sqrt{8}+\sqrt{20} ,$ is closest to \begin{array}{l}\require{cancel} 3+4 \\\\= 7 .\end{array} Hence, $\text{ Choice C .}$
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