Answer
$\frac{y^{2}}{x}$
Work Step by Step
We are given the expression $(x^{-3}y^{6})^{\frac{1}{3}}$.
We can use the power rule, which holds that $(a^{m})^{n}=a^{m\times n}$ (where a is a real number, and m and n are integers).
$(x^{-3}y^{6})^{\frac{1}{3}}=x^{(-3\times\frac{1}{3})}y^{(6\times\frac{1}{3})}=x^{-1}y^{2}=\frac{y^{2}}{x}$
