Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 22



Work Step by Step

$\sqrt (25(x-y)^{2})=\sqrt (25\times(x-y)^{2})=\sqrt 25\times\sqrt((x-y)^{2})=5|x-y|$ We know that $\sqrt 25=5$ because $5^{2}=25$.
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