Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 31



Work Step by Step

$-9^{\frac{3}{2}}=-(\sqrt (9^{3}))=-(\sqrt (9\times9\times9))=-(\sqrt 9\times\sqrt 9\times\sqrt 9))=-(3\times3\times3)=-(27)=-27$ We know that $\sqrt 9=3$, because $3^{2}=9$. In this case, we are finding the opposite of $\sqrt (9^{3})$.
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