Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 468: 27



Work Step by Step

$(\frac{1}{81})^\frac{1}{4}=\sqrt[4] (\frac{1}{81})=\frac{1}{3}$ We know this because $(\frac{1}{3})^{4}=\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}=\frac{1}{81}$
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