Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 18



Work Step by Step

$\sqrt[5] ((-5)^{5})=-5$, because $((-5)^{5})^\frac{1}{5}=(-5)^{5\times\frac{1}{5}}=(-5)^{1}=-5$ We do not need absolute value bars around the result, because the index of the radical is odd in this case.
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