Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review: 26a


2, $\sqrt[3] 17$

Work Step by Step

We are given the function $g(x)=\sqrt[3] (x-3)$. $g(11)=\sqrt[3] (11-3)=\sqrt[3] 8=2$ We know this because $2^{3}=8$. $g(20)=\sqrt[3] (20-3)=\sqrt[3] 17$
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