Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Review - Page 468: 32



Work Step by Step

$64^{-\frac{1}{3}}=\frac{1}{64^{\frac{1}{3}}}=\frac{1}{\sqrt[3] 64}=\frac{1}{4}$ We know that $\sqrt[3] 64=4$, because $4^{3}=4\times4\times4=64$
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