Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 354: 61

Answer

$\dfrac{2x+16}{(x+2)(x+2)(x-2)}$

Work Step by Step

Factoring the given expression, $ \dfrac{5}{x^2-4}-\dfrac{3}{x^2+4x+4} ,$ results to \begin{array}{l} \dfrac{5}{(x+2)(x-2)}-\dfrac{3}{(x+2)(x+2)} .\end{array} Using the $LCD= (x+2)(x+2)(x-2) $, the expression above simplifies to \begin{array}{l} \dfrac{(x+2)(5)-(x-2)(3)}{(x+2)(x+2)(x-2)} \\\\= \dfrac{5x+10-3x+6}{(x+2)(x+2)(x-2)} \\\\= \dfrac{2x+16}{(x+2)(x+2)(x-2)} .\end{array}
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