Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 354: 50

Answer

$\frac{(3x-4)}{(x-2)(x-1)}$

Work Step by Step

Original Equation $\frac{9x+2}{3x^{2}-2x-8}$ + $\frac{7}{3x^{2}+x-4}$ Factor Denominator $\frac{9x+2}{(3x+4)(x-2)}$ + $\frac{7}{(3x+4)(x-1)}$ Find LCD: (3x+4)(x-2)(x-1) Add numerators $\frac{(9x+2)(x-1)+7(x-2)}{(3x+4)(x-2)(x-1)}$ Simplify $\frac{9x^{2}-16}{(3x+4)(x-2)(x-1)}$ Factor Answer: $\frac{(3x-4)}{(x-2)(x-1)}$
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