## Intermediate Algebra (6th Edition)

$-4x(x+3)(x-3)$
The factored form of the expression, $\dfrac{x}{x^2-9} ,$ is \begin{array}{l}\require{cancel} \dfrac{x}{(x+3)(x-3)} .\end{array} The factored form of the expression, $\dfrac{5}{x} ,$ is \begin{array}{l}\require{cancel} \dfrac{5}{x} .\end{array} The factored form of the expression, $\dfrac{7}{12-4x} ,$ is \begin{array}{l}\require{cancel} \dfrac{7}{-(4x-12)} \\\\ \dfrac{7}{-4(x-3)} \\\\ -\dfrac{7}{4(x-3)} .\end{array} Hence, the $LCD$ of the given expressions is \begin{array}{l}\require{cancel} -4x(x+3)(x-3) .\end{array}