Answer
$\frac{y^{2}+2y+10}{(y-2)(y+4)(y-4)}$
Work Step by Step
Original Equation
$\frac{y+1}{y^{2}-6y+8}$ - $\frac{3}{y^{2}-16}$
Factor Denominator
$\frac{y+1}{(y-4)(y-2)}$ - $\frac{3}{(y-4)(y+4)}$
Find LCD: (y-2)(y-4)(y+4)
Add numerators
$\frac{(y+1)(y+4)-3(y-2)}{(y-2)(y+4)(y-4)}$
Simplify
Answer: $\frac{y^{2}+2y+10}{(y-2)(y+4)(y-4)}$
