Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set: 22

Answer

15(a+3)(a-3)

Work Step by Step

The factored form of the expression, $ \dfrac{2}{3a+9} ,$ is \begin{array}{l}\require{cancel} \dfrac{2}{3(a+3)} .\end{array} The factored form of the expression, $ \dfrac{5}{5a-15} ,$ is \begin{array}{l}\require{cancel} \dfrac{5}{5(a-3)} .\end{array} Hence, the $LCD$ of the given expressions is \begin{array}{l}\require{cancel} 15(a+3)(a-3) .\end{array}
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