## Intermediate Algebra (6th Edition)

The factored form of the expression, $\dfrac{2}{3a+9} ,$ is \begin{array}{l}\require{cancel} \dfrac{2}{3(a+3)} .\end{array} The factored form of the expression, $\dfrac{5}{5a-15} ,$ is \begin{array}{l}\require{cancel} \dfrac{5}{5(a-3)} .\end{array} Hence, the $LCD$ of the given expressions is \begin{array}{l}\require{cancel} 15(a+3)(a-3) .\end{array}