Answer
$\frac{2x^{2}+3x+24}{(3x+1)(x-1)(x-6)}$
Work Step by Step
Original Equation
$\frac{x}{x^{2}-7x+6}$ - $\frac{x+4}{3x^{2}-2x-1}$
Factor Denominator
$\frac{x}{(x-1)(x-6)}$ - $\frac{x+4}{(3x+1)(x-1)}$
Find LCD: (3x+1)(x-1)(x-6)
Add numerators
$\frac{x(3x+1)-(x+4)(x-6)}{(3x+1)(x-1)(x-6)}$
Simplify
Answer: $\frac{2x^{2}+3x+24}{(3x+1)(x-1)(x-6)}$
