Answer
$\frac{x^{2}+4x+2}{(x-1)(x-7)(2x+5)}$
Work Step by Step
Original Equation
$\frac{x}{x^{2}-8x+7}$ - $\frac{x+2}{2x^{2}-9x-35}$
Factor Denominator
$\frac{x}{(x-1)(x-7)}$ - $\frac{x+2}{(x-7)(2x+5)}$
Find LCD: (x-7)(2x+5)(x-1)
Add numerators
$\frac{x(2x+5)-(x+2)(x-1)}{(x-1)(x-7)(2x+5)}$
Simplify
Answer: $\frac{x^{2}+4x+2}{(x-1)(x-7)(2x+5)}$
