Answer
$\dfrac{9x+4}{8x-7}$
Work Step by Step
Cancelling the common factors between the numerator and the denominator, the given expression, $
\dfrac{9x^2+13x+4}{8x^2+x-7}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{(9x+4)(x+1)}{(8x-7)(x+1)}
\\\\=
\dfrac{(9x+4)(\cancel{x+1})}{(8x-7)(\cancel{x+1})}
\\\\=
\dfrac{9x+4}{8x-7}
.\end{array}
