Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 408: 40

Answer

$(2x-5)(3x+7)$

Work Step by Step

The $2$ numbers whose product is $ac= 6(35)=210 $ and whose sum is $b= -1 $ are $\{ -15,14 \}$. Using these two numbers to decompose the middle term of the given expression, $ 6x^2-x-35 ,$ then the factored form is \begin{array}{l}\require{cancel} 6x^2-15x+14x-35 \\\\= (6x^2-15x)+(14x-35) \\\\= 3x(2x-5)+7(2x-5) \\\\= (2x-5)(3x+7) .\end{array}
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