Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 408: 45a

Answer

$\dfrac{1}{5x-1}$

Work Step by Step

Cancelling the common factors between the numerator and the denominator, the given expression, $ \dfrac{2x^2}{10x^3-2x^2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2x^2}{2x^2(5x-1)} \\\\= \dfrac{\cancel{2x^2}}{\cancel{2x^2}(5x-1)} \\\\= \dfrac{1}{5x-1} .\end{array}
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