Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 408: 31a

Answer

$4x^{b}$

Work Step by Step

Using the laws of exponents, the given expression, $ x^{-b}(2x^b)^2 ,$ simplifies to \begin{array}{l}\require{cancel} x^{-b}\left( 2^2x^{b(2)} \right) \\\\= x^{-b}\left( 4x^{2b} \right) \\\\= 4x^{-b+2b} \\\\= 4x^{b} .\end{array}
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