Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 408: 30c

Answer

$\dfrac{1}{x^3}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{x^{-5}}{x^{-2}} ,$ simplifies to \begin{array}{l}\require{cancel} x^{-5-(-2)} \\\\= x^{-5+2} \\\\= x^{-3} \\\\= \dfrac{1}{x^3} .\end{array}
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