Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Cumulative Review - Page 408: 32a

Answer

$48x^{2a}$

Work Step by Step

Using the laws of exponents, the given expression, $ 3x^{4a} \left( 4x^{-a} \right)^2 ,$ simplifies to \begin{array}{l}\require{cancel} 3x^{4a} \left( 4^2x^{-a(2)} \right) \\\\= 3x^{4a} \left( 16x^{-2a} \right) \\\\= 48x^{4a+(-2a)} \\\\= 48x^{2a} .\end{array}
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