Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 54



Work Step by Step

Using factoring by grouping, then, \begin{array}{l} 2a^5-a^4+6a-3 \\= (2a^5-a^4)+(6a-3) \\= a^4(2a-1)+3(2a-1) \\= (2a-1)(a^4+3) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.