Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 27



Work Step by Step

Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of two cubes, then, \begin{array}{l} (x+5)^3+y^3 \\= [(x+5)+(y)][(x+5)^2-(x+5)(y)+(y)^2] \\= [x+5+y][(x^2+10x+25)-xy-5y+y^2] \\= (x+5+y)(x^2+10x+25-xy-5y+y^2) .\end{array}
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