## Intermediate Algebra (6th Edition)

Factoring the $GCF= 10x$ results to $10x(x^2-21x+110)$. The two numbers whose product is $110$ and whose sum is $-21$ are $\{-10,-11\}$. Using these numbers to decompose the middle term of the trinomial results to \begin{array}{l} 10x(x^2-21x+110) \\= 10x(x^2-11x-10x+110) \\= 10x[(x^2-11x)-(10x-110)] \\= 10x[x(x-11)-10(x-11)] \\= 10x[(x-11)(x-10)] \\= 10x(x-11)(x-10) .\end{array}