Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 43



Work Step by Step

Factoring the $GCF= 10x $ results to $ 10x(x^2-21x+110) $. The two numbers whose product is $110$ and whose sum is $-21$ are $\{-10,-11\}$. Using these numbers to decompose the middle term of the trinomial results to \begin{array}{l} 10x(x^2-21x+110) \\= 10x(x^2-11x-10x+110) \\= 10x[(x^2-11x)-(10x-110)] \\= 10x[x(x-11)-10(x-11)] \\= 10x[(x-11)(x-10)] \\= 10x(x-11)(x-10) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.