Answer
$(3y-5)(y^4+2)$
Work Step by Step
Using factoring by grouping, then,
\begin{array}{l}
3y^5-5y^4+6y-10
\\=
(3y^5-5y^4)+(6y-10)
\\=
y^4(3y-5)+2(3y-5)
\\=
(3y-5)(y^4+2)
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 49
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
