Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 37

$(5x-11)(2x+3)$

The two numbers whose product is $ 10(-33)=-330 $ and whose sum is $ -7 $ are $\{ -22,15 \}$. Using these numbers to decompose the middle term of the trinomial results to \begin{array}{l} 10x^2-22x+15x-33 \\= (10x^2-22x)+(15x-33) \\= 2x(5x-11)+3(5x-11) \\= (5x-11)(2x+3) .\end{array}