# Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 313: 46

$(y^2+4)(y+2)(y-2)$

#### Work Step by Step

Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of two squares, then, \begin{array}{l} y^4-16 \\= (y^2+4)(y^2-4) \\= (y^2+4)(y+2)(y-2) .\end{array}

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